[考題] 基本電學
有一平行板電容器接於直流電壓源,
其極板電荷量為1000微庫倫,儲存5焦耳能量,
則此電容器之電容量為多少微法拉?
(A)100 (B)10 (C)1 (D)0.1
我的算法如下
W=Q*V
5=0.001*V
V=5000
W=1/2*C*V平方
5=1/2*C*5000平方
C=...沒有在選項裡><
我是哪裡算錯了啊~救命啊~~~求救高手~~~
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