Re: [問題] 十階濾波器?
y(n)=0.1*[ x(n) + x(n-1) + x(n-2) + x(n-3) + x(n-4) + x(n-5) + x(n-6)
+x(n-7) + x(n-8) + x(n-9) ]
推
07/11 01:26,
07/11 01:26
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07/11 01:27,
07/11 01:27
繼續從continuous-time的角度看,設sampling period為T
則 z = e^jwT 代入 H(z)
又假設信號頻率w << sampling frequency 1/T
得到 z = e^jwT = cos(wT) + j*sin(wT) = j*sin(wT) = jwT
以上就變成
H(jw) = 1 + 1/jwT + 1/(jwT)^2 + ...........
的確是一個低通濾波器的形式
另外要濾生理信號,如果是低通濾波的目的,要濾除高頻雜訊
用到十階的digital filter是殺蚯蚓用屠龍刀
如果有雜訊需要在數位部份用到這麼sharp的東西
那這個系統design一定有問題,analog進來的東西很髒,早就爆掉了
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◆ From: 118.168.2.141
※ 編輯: jamtu 來自: 118.168.2.141 (07/11 04:21)
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