Re: [問題] hspice輸入語法可以寫出數學模型嗎
臨時找不到hspice的manual
這個給你做個參考，因為我也不知道能不能用XD
http://newton.ex.ac.uk/teaching/cdhw/Electronics2/userguide/sec3.html
3.2.3 Non-linear Dependent Sources
General form:
BXXXXXXX N+ N- <I=EXPR> <V=EXPR>
Examples:
B1 0 1 I=cos(v(1))+sin(v(2))
B1 0 1 V=ln(cos(log(v(1,2)^2)))-v(3)^4+v(2)^v(1)
B1 3 4 I=17
B1 3 4 V=exp(pi^i(vdd))
N+ is the positive node, and N- is the negative node. The values of the V and
I parameters determine the voltages and currents across and through the
device, respectively. If I is given then the device is a current source, and
if V is given the device is a voltage source. One and only one of these
parameters must be given.
[Note: The SPICE3 non-linear sources are not compatible with the poly()
syntax used in SPICE2. Appendix C is included to facilitate conversion of old
source. CDHW.]
[Note: Appendix D describes several bugs affecting these devices. CDHW.]
The small-signal AC behavior of the nonlinear source is a linear dependent
source (or sources) with a proportionality constant equal to the derivative
(or derivatives) of the source at the DC operating point.
The expressions given for V and I may be any function of voltages and
currents through voltage sources in the system. The following functions of
real variables are defined:
abs asinh cosh sin
acos atan exp sinh
acosh atanh ln sqrt
asin cos log tan
The function "u()" is the unit step function, with a value of one for
arguments greater than zero and a value of zero for arguments less than or
equal to zero. The function uramp(x) is the integral of the unit step: for an
input x, the value is zero if x is less than zero, or if x is greater than or
equal to zero the value is x. These two functions are useful in sythesizing
piece-wise non-linear functions, though convergence may be adversely affected.
The following standard operators are defined:
+ - * / ^ unary -
If the argument of log(), ln(), or sqrt() becomes less than zero, the
absolute value of the argument is used. If a divisor becomes zero or the
argument of log() or ln() becomes zero, an error will result. Other problems
may occur when the argument for a function in a partial derivative enters a
region where that function is undefined.
To get time into the expression you can integrate the current from a constant
current source with a capacitor and use the resulting voltage (don't forget
to set the initial voltage across the capacitor). Nonlinear resistors,
capacitors, and inductors may be synthesized with the nonlinear dependent
source. Nonlinear resistors are obvious. Nonlinear capacitors and inductors
are implemented with their linear counterparts by a change of variables
implemented with the nonlinear dependent source. The following subcircuit
will implement a nonlinear capacitor:
.Subckt nlcap pos neg
* Bx: calculate f(input voltage)
Bx 1 0 v = f(v(pos,neg))
* Cx: linear capacitance
Cx 2 0 1
* Vx: Ammeter to measure current into the capacitor
Vx 2 1 DC 0Volts
* Drive the current through Cx back into the circuit
Fx pos neg Vx 1
.ends
Non-linear inductors are similar.
※ 引述《maipeter (阿sir)》之銘言：
: 求助問題如標題，因為跑模擬時 輸入的訊號為一個無法用sin波描述出的波形
: 那波形是由線性及非線性組合而成 是有數學函式
: 但就不知道Hspice撰寫語法裡 有可以描述數學函式的語法嗎
: 謝謝各位先輩了
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