[作業] 總成本 & 邊際成本

看板Economics作者 (Kevin凱文)時間11年前 (2012/11/04 13:37), 編輯推噓6(6推 0噓 4→)
留言10則, 3人參與, 最新討論串1/2 (看更多)
學校: 教師: 科目: 個體經濟 題目: Zoe is trying to decide how to divide her time between her job as a wedding photographer, which pays $27 per hour for as many hours as she chooses to work, and as a fossil collector, in which her pay depends both on the price of fossils and the number of them she finds. Earnings aside, Zoe is indifferent between the two tasks, and the number of fossils she can find depends on the number of hours a day she searches, as shown in the table below: Hours per day Total fossils per day 　　　１　　　　　　　　　　５ 　　　２　　　　　　　　　　９ 　　　３　　　　　　　　　１２ 　　　４　　　　　　　　　１４　　 　　　５　　　　　　　　　１５ ※請計算 TC 與 MC　 我的想法: 之前寫的題目都是有給予確切的成本函數， 老師改成這樣的題目實在有點沒頭緒， 還請各位幫忙一下，謝謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.47.147.239
推
11/04 14:22, , 1F
定義沒變阿，只是間段型資料怎會不知？
11/04 14:22, 1F
→
11/04 14:38, , 2F
brother, 你知道函數有分連續函數和非連續函數嗎...
11/04 14:38, 2F
推
11/04 22:36, , 3F
機會成本的題目喔......
11/04 22:36, 3F
推
11/04 22:50, , 4F
生產函數 Q=5.5t-0.5t^2 XDD
11/04 22:50, 4F
推
11/04 22:55, , 5F
連續dQ/dT=5.5-t, 不連續dQ/dT=5-t
11/04 22:55, 5F
→
11/04 22:56, , 6F
更正: 6-t
11/04 22:56, 6F
→
11/04 22:57, , 7F
MC= 27xdT/dQ = 27/(5.5-t) 或 27/(6-t)
11/04 22:57, 7F
推
11/04 23:25, , 8F
T=5.5-(30.25-2Q)^0.5
11/04 23:25, 8F
→
11/04 23:26, , 9F
MC(Q)=27/[(30.25-2Q)^0.5]
11/04 23:26, 9F
推
11/04 23:30, , 10F
TC(Q)=27T=148.5-27x(30.25-2Q)^0.5
11/04 23:30, 10F
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文章代碼(AID): #1GbVyIJh (Economics)
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文章代碼(AID): #1GbVyIJh (Economics)