[SQL ] 請問如何相減再 group 起來?

看板Database作者 (prepare myself)時間8年前 (2015/09/10 06:09), 編輯推噓0(001)
留言1則, 1人參與, 最新討論串1/2 (看更多)
+-------+-------+--------+---------+ | att1 | att2 | in/our | time | +-------+-------+--------+---------+ | A | B | in | 7:00 | +-------+-------+--------+---------+ | C | D | out | 7:50 | +-------+-------+--------+---------+ | A | B | out | 7:20 | +-------+-------+--------+---------+ | C | D | in | 7:10 | +-------+-------+--------+---------+ 請問如何下 SQL 計算時間差再 group 起來呢..? 結果希望像下面這樣..苦手中.. +-------+-------+-------------------+ | att1 | att2 | time_diff | +-------+-------+-------------------+ | A | B | 10 | +-------+-------+-------------------+ | C | D | 40 | +-------+-------+-------------------+ -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.160.87.217 ※ 文章網址: https://www.ptt.cc/bbs/Database/M.1441836598.A.5D7.html

09/10 23:24, , 1F
第一列算出來是10?還是20
09/10 23:24, 1F
文章代碼(AID): #1LyAusNN (Database)
文章代碼(AID): #1LyAusNN (Database)