Re: [問題]普通化學或有機化學

看板Chemistry作者reckson1017 (GOD)時間18年前 (2006/04/05 21:04)推噓2(2推 0噓 0→)

留言2則, 2人參與討論串2/2 (看更多)

※ 引述《kijhao (。)》之銘言： : We can calculate the percentages of two isomers at equilibrium : using the equation △E=-R*T*lnK . : △E is the energy difference between isomers : R is the gas constant : T is the Kelvin temperature : K is the equilibrium constant between isomers : 請問若已知的數據有△E , R , T , K : 那要怎麼代公式求存在的百分比? : 題目如下: : The energy difference of 3.8 (KJ/mol) between gauche and anti butance : corresponds to an equilibrium constant Keq of approximately 1.9 : Calculate the percentage of each conformer at equilibrium. : 感謝各位大大的解答 .......................不對就算了................................. Ksp=1.9 若兩者平衡令a=b達到平衡 1-x=x 則1.9=x/(1-x) 求得解離常數我覺得△E , R , T , K是用不到的這是我的感覺拉看看有沒有強者來說說對不對 ...................................................................... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 203.73.104.25

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Obiwang

04/05 23:00, , 1^F

04/05 23:00, 1^F

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kijhao

04/06 21:08, , 2^F

04/06 21:08, 2^F

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