[問題] address operator &
網址:
https://stackoverflow.com/questions/49890211/address-operator-and-array-in-assembly-level
在Answer裡面提到:
The address of & operator allows you to construct a pointer to value from a
variable of same type as value.
中文翻譯:address operator允許你建構一個指標(from一個變數to value，且這個變數有
跟value一樣的type)
請問，這一行的意思是不是指，當執行程式這一行時:
p = &var1;
&本身也會占用一個variable的空間(用來放var1的address)，然後在把這個address給p?
接下來，內文提到:
int *p = &A;
程式在做這行指令時，you are doing an assignment from a pointer to array of int
into a variable of type array of int, which is a different type.
光看這行英文，哪有different type，一樣是array of int啊
還是他打錯了?應該是from a pointer to int into a variable of type array of int?
謝謝。
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