雙重指標問題

看板C_and_CPP作者harristime (瀚宇)時間7年前 (2017/04/10 23:34)推噓3(3推 0噓 5→)

留言8則, 4人參與討論串1/1

各位朋友們好，最近我在研究雙重指標的用法，有個問題一直想不出來為什麼Ｃｏｄｅ： int main() { char *name = "Rick"; char **pp = &name; printf("string Rick is stored in %p\n", name); printf("name's address is in %p\n", &name); printf(" **pp's address is %p\n", &pp); printf(" *pp with %/p = %p\n", *pp);　 printf(" *pp with %/s = %s\n", *pp);　　／／這行反倒可以解出內容　’Ｒｉｃｋ’ printf(" **pp's dereference = %s\n", **pp);　　／／　我想解出內容，但出現警告與Ｓｅｇｍｅｎｔａｉｏｎ　ｆａｕｌｔＲｅｓｕｌｔ： string Rick is stored in 0x8048530 name's address is in 0xbf9e9c9c **pp's address is 0xbf9e9c98 *pp with %/p = 0x8048530 *pp with %/s = Rick Segmentation fault 為什麼Ｒｉｃｋ是使用　＊ｐｐ解出來而不是＊＊ｐｐ呢？為什麼　＊ｐｐ可以同時解出字串存放的位置跟字串內容呢？　謝謝 -- Sent from my Windows -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 36.228.2.202 ※ 文章網址: https://www.ptt.cc/bbs/C_and_CPP/M.1491838496.A.4FE.html

推

LPH66

04/10 23:57, , 1^F

04/10 23:57, 1^F

→

LPH66

04/10 23:57, , 2^F

04/10 23:57, 2^F

→

LPH66

04/10 23:58, , 3^F

04/10 23:58, 3^F