[問題] 用 bitwise operator 把十進位轉成二進位
開發平台(Platform): (Ex: VC++, GCC, Linux, ...)
Dev-C++, Win7
餵入的資料(Input)：
3
預期的正確結果(Expected Output)：
000
001
010
011
100
101
110
111
錯誤結果(Wrong Output)：
000
111
000
111
000
111
000
111
程式碼(Code)：(請善用置底文網頁, 記得排版)
int length,i,j;
char *binary = 0;
length = (int) ceil( log(n)/log(2) );
binary = (char*) malloc( sizeof(char)*(length+2) );
binary[length+1] = NULL;
for( i = 0; i < pow(2,n); i++ )
{
for( j = length; j >= 0; j-- )
{
if( n&1 )
binary[j] = '1';
else
binary[j] = '0';
n >> 1;
}
printf("%s\n",binary);
}
補充說明(Supplement)：
這幾天才剛開始學 C (之前是學C++,不過也沒有很紮實..)
希望問的問題不會太笨 >"<
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