這是一個把文字16進位轉換成二進位的小程式
1 #include <cstdlib>
2 #include <iostream>
3 #include <fstream>
4
5 using namespace std;
6
7 int main(int Argc, char *Argv[])
8 {
9 string FileNameIn(Argv[1]);
10 string Temp;
11 unsigned int Ch;
12
13 ifstream FileIn(FileNameIn.c_str());
14 ofstream FileOut((FileNameIn + ".out").c_str(), ios::binary);
15
16 cout << FileIn << endl;
17 while(FileIn >> Temp)
18 {
19 sscanf(Temp.c_str(), "%02X", &Ch);
20 FileOut << (char)Ch;
21 }
22 cout << FileIn << endl;
23
24 FileOut.close();
25 FileIn.close();
26
27 system("PAUSE");
28 return EXIT_SUCCESS;
29 }
我有一些問題
1.
我用 Dev-C++ 4.9.9.2 for mingw32 3.4.5 來進行編譯是成功的且正確執行。
但是我用 Microsoft Visual C++ 6.0 結果出現以下訊息：
Compiling...
main.cpp
C:\hex2bin\main.cpp(14) : error C2784: 'class std::reverse_iterator<_RI,
_Ty,_Rt,_Pt,_D> __cdecl std::operator +(_D,const class std::reverse
_iterator<_RI,_Ty,_Rt,_Pt,_D> &)' : could not deduce template argument
for '' from 'class std::basic_string,class std::allocator >'
C:\hex2bin\main.cpp(14) : error C2676: binary '+' :
'class std::basic_string,class std::allocator >' does not define this
operator or a conversion to a type acceptable to the predefined operator
C:\hex2bin\main.cpp(14) : error C2228: left of '.c_str' must have
class/struct/union type
C:\hex2bin\main.cpp(17) : error C2679: binary '>>' : no operator defined
which takes a right-hand operand of type 'class std::basic_string,class
std::allocator >' (or there is no acceptable conversion)
C:\hex2bin\main.cpp(17) : fatal error C1903: unable to recover
from previous error(s); stopping compilation
Error executing cl.exe.
這表示我不能這樣寫嗎？那為什麼 Dev-C++ 卻可以呢？
2.
第 16 行和第 22 行分別顯示 FileIn 物件執行前和執行後的指標。
結果是：
0x22fe84
0
如果第二個顯示是 0 那我第 25 行程式還有執行的意義在嗎？
謝謝大家
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