Re: [問題] 請問rpm與g之換算
※ 引述《graddivcurl.bbs@ptt.cc (為所應為)》之銘言:
> ※ 引述《swordfish.bbs@bbs.nchu.edu.tw (高義!你真他媽的雜碎)》之銘言:
> : 請大大幫幫忙^^
感謝大大^^ (跪謝...)
> (1) Because rpm is revolution(s) per minute,
> rpm = (w/(2Pi))*60 where w is radian/sec
> Thus, w=(Pi/30)*rpm
> (2) a=rw^2 (because a=(v^2)/r, & v=rw)
> (3) RCF (relative centrifugal force) is defined as
> RCF= (a/g)= (rw^2)/980 = {r[(Pi/30)*rpm]^2}/980
> =1.119* 10^(-5) * (rpm)^2 * r
> done!
--
Ξ Origin: 中興大學天樞資訊網 <bbs.nchu.edu.tw>
Ξ From : 218-162-100-158.dynamic.hinet.net
討論串 (同標題文章)
完整討論串 (本文為第 9 之 9 篇):
問題
2
2