Re: [問題] 請問rpm與g之換算

看板Biology作者時間17年前 (2006/09/19 02:01), 編輯推噓0(000)
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※ 引述《graddivcurl.bbs@ptt.cc (為所應為)》之銘言: > ※ 引述《swordfish.bbs@bbs.nchu.edu.tw (高義!你真他媽的雜碎)》之銘言: > : 請大大幫幫忙^^ 感謝大大^^ (跪謝...) > (1) Because rpm is revolution(s) per minute, > rpm = (w/(2Pi))*60 where w is radian/sec > Thus, w=(Pi/30)*rpm > (2) a=rw^2 (because a=(v^2)/r, & v=rw) > (3) RCF (relative centrifugal force) is defined as > RCF= (a/g)= (rw^2)/980 = {r[(Pi/30)*rpm]^2}/980 > =1.119* 10^(-5) * (rpm)^2 * r > done! -- Ξ Origin: 中興大學天樞資訊網 <bbs.nchu.edu.tw> Ξ From : 218-162-100-158.dynamic.hinet.net
文章代碼(AID): #153jxu00 (Biology)
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文章代碼(AID): #153jxu00 (Biology)