Design a combinational circuit with three inputs and one output.
(a) The output is 1 when the binary value of the inputs is less
than 3 and greater than 6. The output is 0 otherwise.
我想真值表應該是這樣
A B C Output
0 0 0 1
0 0 1 1
0 1 0 1
0 1 1 0
1 0 0 0
1 0 1 0
1 1 0 0
1 1 1 1
再由卡諾圖推出
F= A'B'+A'C'+ABC
= A'(B'+ C')+A(B'+ C')'
= A XOR (B'+C')
可是書本的答案是 F= A XOR (BC)
請問我哪邊弄錯了?
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※ 編輯: kattte (111.242.19.125), 05/25/2014 23:53:01
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05/25 23:55, , 1F
05/25 23:55, 1F
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05/26 00:18, , 2F
05/26 00:18, 2F
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05/26 18:17, , 3F
05/26 18:17, 3F
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05/27 00:25, , 4F
05/27 00:25, 4F