[問題] 2階ODE
已知y1(x)=exp(2x)為(x+2)y"-(2x+5)y'+2y=0之一解,
求(x+2)y"-(2x+5)y'+2y=(x+1)exp(x),y(0)=y'(0)=1之解
先解出來的人 明年我會送他我的台大學生證影本
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