[電磁] 算不同介電常數電容的問題

看板TransPhys作者 (unknown)時間16年前 (2009/04/26 15:56), 編輯推噓1(1推 0噓 5→)
留言6則, 1人參與, 最新討論串1/1
A parallel-plate capacitor with a plate separation d has a capacitance C1. A slab of dielectric material of dielectric constant K and thickness d is inserted between the plates. (A)Calculate the new capacitance C2 with the dielectric slab. (B)If thickness of the inserted dielectric slab is d/2,calculate the new capacitance C3 with the dielectric slab. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.224.29.124
推
05/04 14:21, , 1F
(A) C2=KC1 方法:先假設帶電Q由電場高斯定律求出E
05/04 14:21, 1F
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05/04 14:24, , 2F
註:還要假設電界質產生感應電荷q~然後....
05/04 14:24, 2F
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05/04 14:26, , 3F
最後得到:C2=[Q/(Q-q)]C1~~其中[Q/(Q-q)]=K
05/04 14:26, 3F
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05/04 14:29, , 4F
(B) 看成兩電容串連(一含電界質K另一個不含~板距都d/2)
05/04 14:29, 4F
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05/04 14:31, , 5F
1/C3=1/2KC1+1/2C1 得C3
05/04 14:31, 5F
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05/04 14:34, , 6F
註解:平行板電容推導:先設Q~由高斯得E~積分得V帶入C=Q/V
05/04 14:34, 6F
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