[電磁] 93中興
The switch S of the circuit shown in the accompanying
figure is closed at t=0, at which time C_2 is uncharged
and the voltage across C_1 is V. Show that the charge
on the capacitors are given by
-t/a
C_1+C_2 * e
q_1(t) = {------------------)C_1 * V
C_1+C_2
C_1*C_2*V -t/a
q_2(t) = {-----------}(1-e )
C_1+C_2
where a = RC_1*C_2/(C_1+C_2) (17%)
R
________ ________
| ^^^^ |
| |
| |
--- C_1 --- C_2
--- ---
| |
| ╲ |
|__________ ╲______|
S
題目要證明的是q_1和q_2 標黃色的部分
謝謝摟^^
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