[問題] 擲骰子的條件機率

看板Statistics作者 (nourri)時間15年前 (2010/10/11 11:40), 編輯推噓2(206)
留言8則, 3人參與, 最新討論串1/1
不好意思 有一個很簡單的問題一直搞不懂>< A pair of four sided dice is rolled and the sum is determined. In a sequence of rolls the probability that a sum of 3 is rolled before a sum of 5 is rolled can be thought of as the conditional probability of a sum of 3 given that a sum of 3 or 5 has occurred. 雖然上面教了方法 但是我搞不懂為什麼可以這樣解釋 懇請高手賜教 謝謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 96.251.58.58

10/13 14:05, , 1F
independent
10/13 14:05, 1F

10/13 14:16, , 2F
因為 sum=3 or sum=5 發生事件就決定了.
10/13 14:16, 2F

10/13 14:18, , 3F
而發生 sum=3 是題目定的事件. 所以可以這樣來計算.
10/13 14:18, 3F

10/13 22:32, , 4F
謝謝
10/13 22:32, 4F

11/11 16:34, , 5F
這個問題我覺得沒想像的直覺跟簡單,用乘法原理畫圖
11/11 16:34, 5F

11/11 16:36, , 6F
再解無窮級數。參考下面文件43頁下面開始
11/11 16:36, 6F

11/11 16:36, , 7F
erdos.math.louisville.edu/~pksaho01/teaching/
11/11 16:36, 7F

11/11 16:37, , 8F
Math662TB-09S.pdf
11/11 16:37, 8F
文章代碼(AID): #1CieScdt (Statistics)