[問題] 請問該用哪一種無母數來解此題
這是某年的考古題
Two health inspectors rate 11 hospitals on cleanliness, as shown in the
tabulation that follows. Determine whether their rankings are comparable.
Assume that differences of their rankings are not normally distributed.
Hospital
---------------------------------------------
1 2 3 4 5 6 7 8 9 10 11
---------------------------------------------
Inspector 1 2 3 2 3 1 4 5 3 1 3 4
Inspector 2 1 3 3 2 2 5 4 2 1 4 3
---------------------------------------------
Q: State the null hypothesis and perform the appropriate test and calculate
the p value.
Note:
binominal probabilities (p=0.5)
--------------------------------------------------------------------------
k 0 1 2 3 4 5 6 7 8 9 10 11
n=9 0.02 0.018 0.070 0.164 0.246 0.246 0.164 0.070 0.018 0.002
n=10 0.001 0.010 0.044 0.117 0.205 0.246 0.205 0.117 0.044 0.010 0.001
n=11 0.000 0.005 0.027 0.081 0.161 0.226 0.226 0.161 0.081 0.027 0.005 0.000
--------------------------------------------------------------------------
題目講明了母體不是常態分布，所以應該是用無母數統計法來算
小弟手邊的書沒有專門講無母數的
會的無母數統計法也不多，看到題目的第一個瞬間只想到用
"wilcoxon rank sum test" 或是 Spearman's r
仔細看題目題義跟Note附表，感覺上好像是rank sum test比較對
不知道小弟這樣的想法有沒有錯？ 還是應該用哪一種檢定法會比較適合呢？
另外..這虛無假說該怎麼設定會比較好？
設:此兩調查員的評比結果互相有關？ 還是評比相同？
試著用rank sum test 解出來的 u=min{u1,u2}=46.5
好像又跟查表有點對不太起來..
還是說把兩調查員的評比相減,用符號檢定法來做呢？
如此一來..這個表要怎麼查才好？
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※ 編輯: hyde7621 來自: 59.127.159.118 (04/23 18:41)
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