[問題]請問這題證明 該如何做
5.32 use repeated integration by parts to show that
x 弃
砥 财ye-财 / (y!) = 1/(x!) 凯 txe-t dt
y=0 财
This result is important because values of the
distribution function of a Poisson random
variable may thus be obtained by referring to
a table of incomplete gamma functions
謝謝~
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