[問題] 內積求夾角 計算精確度不足時
兩向量(x,z) (x1,z1)求夾角
公式thita =
cos^-1((x * x1 + z * z1) / (((x * x + z * z) * (x1 * x1 + z1 * z1))^0.5));
但是當(x,z)=(-0.08, 9.7)
(x1,z1)=(-0.08, 9.8)時
Math.acos裡的值會大於1
造成thita=NaN
請問這要怎麼解決呢?
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