[二技] 99年度二技統測管二類會計學正解

看板Polytechnic作者 (NCCU Accounting)時間15年前 (2010/04/26 00:27), 編輯推噓1(101)
留言2則, 2人參與, 最新討論串1/1
核對完畢。成績為滿分 這份擬答分享給今天剛考完二技,想對答案的考生們。 剛剛利用約半個小時作答+打字完畢。 若有偏誤,敬請指正。 ※ [本文轉錄自 TransEcoAcc 看板] 作者: vance0519 (NCCU Accounting) 看板: TransEcoAcc 標題: [會計] 99年度二技統測管二類會計學擬答 時間: Mon Apr 26 00:12:53 2010 1.D 2.C 400,000/800,000x(800,000-500,000)=150,000 3.A 4.C 600,000/800,000x(80,000+100,000)=135,000 [(600,000-135,000)+135,000]/(800,000-180,000+130,000)=0.8 280,000x0.8=224,000 [(600,000-135,000)+135,000]-224,000=376,000 5.C (1,000,000-200,000)/5x3=480,000 1,000,000-480,000=520,000 Min(520,000, 350,000)=350,000 520,000-350,000=170,000 6.B 1,000x5%x1,000=50,000 50,000-30,000=20,000 7.B 40,000/4x(1-2%)=9,800 8.D 200x100,000x6%x3=3,600,000 5,600,000-3,600,000=2,000,000 2,000,000/1,000,000x10,000=20,000 200x2,000x6%x3=72,000 20,000+72,000=92,000 9.B 10.C 11.A 5,000,000x12%/12=50,000 80,888-50,000=30,888 12.A 200,000x0.8+5,000+500=165,500 13.A 107,581x10%/2=5,379 14.B 15.B 16.A 20,000x0.6-2,000=10,000 15,000-10,000=5,000 17.D 18.D 19.B 220,000-20,000+30,000+12,000+1,200=243,200 20.D 21.D 22.C 23.C 24.C (1,500,000+300,000-150,000+60,000)x(1-25%)=1,282,500 25.B 26.A 27.D 28.A 29.C 30.A 31.D 32.C 33.C 34.B 35.A 36.D 37.B 460,000+240,000=700,000 38.B 266,200/(1.1)^2x0.1=22,000 39.D 3,000-250-2,710=40 40.B Xx(1+5%)^2=441,000 X=400,000 41.C 42.D (600,000-40,000)x2%=11,200 43.B -20,000+60,000=40,000 40,000/800,000=5% 44.D 10,000(1+6%x2/12)=10,100 10,100-10,024.25/10,100x12/1=9% 45.A 14,000-6,000+2,000=10,000 300,000x5%=15,000 15,000-10,000=5,000 46.C (490,000-90,000)/4x2=200,000 490,000-200,000=290,000 47.A (2,500,000-500,000)/400,000x80,000=400,000 48.B 840,000+400,000x80%-100,000x80%=1,080,000 49.B 105,400x6%/2=3,162 50.C 1,000+100-500=600 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.170.125.205 ※ 編輯: vance0519 來自: 218.170.125.205 (04/26 00:56)

04/26 18:13, , 1F
滿分耶!!!
04/26 18:13, 1F
※ 編輯: vance0519 來自: 59.120.228.177 (04/26 20:01)

04/26 20:01, , 2F
謝謝學長。
04/26 20:01, 2F
※ 編輯: vance0519 來自: 218.170.120.90 (04/26 22:38)
文章代碼(AID): #1Br6rjBp (Polytechnic)