[問題] 一題基礎流體力學之問題
Dear 各位高手,
資質貧弱之小弟我最近在線上修一門基礎流體力學的課程, 下面的題目是我遇到的問題, 還請不吝賜教。
Question 1
平滑管, 直徑=0.02m, flow rate=0.005 m3/s. 假定kenematic vis =1.787 X 10 -6次方 m2/s
fluid density(water) =1000 kg/m3, what's the pressure drop per meter of pipe ?
我的想法是, always先算出雷諾數Re, 判斷是Turbulent or Laminar,
Re = Vavg * D / Kenematic vis
我的Vavg算出來是15.92m/s (0.005/3.14*0.01*0.01)
Re = 15.92 * 0.02 / 1.787*10-6 = 178176 [Turbulent]
所以我應該用的是"Turbulent / Smooth Pipe的公式去算delta P",
書上對此公式以及我的計算過程如附圖，雖然這題我不知道答案但選項也附上給大家。
(A)101 Kpa/m
(B)311 Kpa/m
(C)214 Kpa/m
(D)180 Kpa/m
懇請賜教了, 謝謝 !!
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