http://miupix.cc/pm-XD3OJ3
http://miupix.cc/pm-56WS8R
我試著另外用力學能守恆下去解
大球落地且靜止,下降2m
則小球上升1m
故(2)(g)(2) = (1)(g)(1) + (0.5)(1)(v)^2
解得小球上升1m時還有速度v
且 v^2 = 6g
所以會再往上衝 (v^2)/2g = 3
這樣就變離地2+1+3了
(正解為2+1+1/3)
不知盲點為何?
--
※ 文章網址: https://www.ptt.cc/bbs/Physics/M.1435403388.A.714.html
→
06/27 19:26, , 1F
06/27 19:26, 1F
→
06/27 19:43, , 2F
06/27 19:43, 2F
→
06/27 19:52, , 3F
06/27 19:52, 3F
→
06/27 20:48, , 4F
06/27 20:48, 4F
→
06/27 20:48, , 5F
06/27 20:48, 5F
另開戰場
http://miupix.cc/pm-ZLS9P4 第6題 想請問
nRT
若是用P=---看,因氣體定量定容,P正比於T
V
又,題目給: T P
273K 76 cmHg
298K 88 cmHg
x 112 cmHg
所以 x 112
--=-- 不是嗎?但這樣解出來x=379.27K = 106.27度C,錯
298 88
不知為什不能這樣解?
※ 編輯: ntuyeh (114.27.49.217), 06/28/2015 00:22:45
推
06/28 01:12, , 6F
06/28 01:12, 6F
→
06/28 01:12, , 7F
06/28 01:12, 7F
推
06/28 01:14, , 8F
06/28 01:14, 8F
→
06/28 01:39, , 9F
06/28 01:39, 9F
→
06/28 01:41, , 10F
06/28 01:41, 10F
→
06/28 01:41, , 11F
06/28 01:41, 11F
→
06/28 01:43, , 12F
06/28 01:43, 12F
→
06/28 01:44, , 13F
06/28 01:44, 13F
→
06/28 01:45, , 14F
06/28 01:45, 14F
推
06/29 00:57, , 15F
06/29 00:57, 15F
→
06/29 17:33, , 16F
06/29 17:33, 16F