[問題] 請問一題波動
Find the diameter of the eye structure that causes a circular diffraction
pattern with the first dark ring at an angle of 3.7 ° when viewed with
monochromatic light of wavelength 590nm . (Typical eye structures of this
type have diameters on the order of 10 μm. Also, the index of refraction of
the vitreous humor is 1.336.)
我的答案
λn = λ/n = 590 nm/1.336 = 441.6168 nm
sinθ = λn/a
>>> a = λn/sinθ = 0.4416168*10^-6/sin3.7 = 6.83 * 10^-6 m = 6.83 μm
但答案不對
請問錯在哪裡
感謝感謝
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