[解題] 景美女中教師甄試(物理)
1.年級：二年級
2.科目：物理
3.章節：
功、動能、位能
4.題目：
http://ppt.cc/CCLH
5.想法：
（1)初未能 = fd、末位能 = fd/3
(2)初未能 + 初動能 = 末位能 + 末動能
(3)末動能 = 2/3 fd
2
(4)1/2(減縮質量）x(相對速度) = 2/3fd
1/2
求出相對速度 = (2fd/m)
1/2
2m的速度 = 1/3相對速度 = [(2fd/m) ] / 3
1/2
(5)2m的動量 = 2m x [(2fd/m) ] / 3
跟答案不一致，不知道問題在哪邊。謝謝各位了!!
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※ 編輯: shmily000 來自: 123.240.109.179 (06/24 20:12)
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