[問題] 關於質心
一根不均勻的木棒
左端定為0點 右端定為L
木棒的重量隨著在哪點而改變
密度函數為ax^2 0<=x<=L
算法一
L
∫ ax^2*xdx
0
Xcm=-------------=3/4
L
∫ ax^2dx
0
算法二
Xcm L
∫ ax^2dx=∫ ax^2dx
0 Xcm
Xcm=[4^(1/3)]/2
為什麼算出來不一樣
請強者解答
謝謝
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