[題目] 考古題

看板Physics作者 (WOW)時間15年前 (2010/06/27 14:53), 編輯推噓0(003)
留言3則, 2人參與, 最新討論串1/1
[領域] 位能 (題目相關領域) [來源] 考古題 [題目]U(x)=kx^2/2+A*exp(-ax^2) where k,A,a are constant Suppose a particle of mass m moving with this potential energy has a velocity v when its position is x=a, Show that the particle doesn't pass through the origin unless A≦mv^2+ka^2/2{1-exp(-ax^2)} [瓶頸] 我把F=-▽U(x)算出來 大概描一下圖形就不知道該怎麼做下去了 謝謝~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 58.99.62.43

06/27 15:17, , 1F
能量守恆就好了. 不過答案不對.
06/27 15:17, 1F

06/27 15:19, , 2F
A<(mv^2+ka^2)/2/{1-exp(-a^3)} 才對
06/27 15:19, 2F

06/27 15:31, , 3F
懂了~謝謝啦~
06/27 15:31, 3F
文章代碼(AID): #1C9lLLQT (Physics)