<?php
$link = mysql_connect("localhost", "root", "123456") or die("無法開啟MySQL資料庫連結!<br>");
$dbname="1234";
mysql_select_db($dbname);
$query_ccdd = "UPDATE `login` SET id='999',pw='999' where id='789'";
$ccdd = mysql_query($query_ccdd) or die(mysql_error());
$row_ccdd = mysql_fetch_assoc($ccdd);
$totalRows_ccdd = mysql_num_rows($ccdd);
?>
請問一下，他都說我的7 8行有問題，請問一下是什麼問題呀~
Warning: mysql_fetch_assoc(): supplied argument is not
a valid MySQL result resource
因為我發覺這一個都會有問題~請問一下各位先進了~感激不盡
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