問題calculus

看板NTUMEB92-HW作者ddkuo3000 (Free your mind.)時間20年前 (2004/01/06 21:43)推噓7(7推 0噓 0→)

留言7則, 3人參與討論串1/1

∫ (1/2x-1) dx 未啥不能把1/2提出 u = x - 1/2 substitude , then solve 1/2 * ∫ [1/(x - 1/2)] dx = 1/2 * ln(x - 1/2) but actually it's u = 2x - 1 ∫ (1/2x-1) dx = 1/2 * ln(2x - 1) WHY????? -- GGGGGGGGG GGGGGGGGG GG GG GG GG TM GGG GGG GG GG GG GG GG GG GG GG GG GG GG GGG GGGG GG GGG GG GG GGGG GGG GG GGG GG GGG GGG GG GGGGGGGGG GGGGGGGGG GGGGGGGG GGG ※ 編輯: ddkuo3000 來自: 218.166.72.5 (01/06 21:53)

推

KILDess

推140.112.249.240 01/06, , 1^F

推140.112.249.240 01/06, 1^F

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KILDess

推140.112.249.240 01/06, , 2^F

推140.112.249.240 01/06, 2^F

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ddkuo3000

推 218.166.72.5 01/06, , 3^F

推 218.166.72.5 01/06, 3^F