[吸痂] 模考參考答案
一、設計學生類別存三科成績 兩個子類別男學生女學生存軍訓護理
class stu
{
protected:
string id, name;
float eng, math, com, sum; // sum=三科加總
public:
void setId(string i) { id = i; }
string getId() { return id; }
void setName(string n) { name = n; }
string getName() { return name; }
void setEng(float e) { eng = e; }
float getEng() { return eng; }
void setMath(float m) { math = m; }
float getMath() { return math; }
void setCom(float c) { com = c; }
float getCom() { return com; }
void setSum() { sum = eng + math + com; }
float getSum() { return sum; }
};
class boy : public stu
{
float mil, sum2; // sum2=四科加總
public:
void setMil(float m) { mil = m; }
float getMil() { return mil; }
void setSum2() { sum2 = eng + math + com + mil; }
float getSum2() { return sum2; }
};
class girl : public stu
{
float nur, sum2; // sum2=四科加總
public:
void setNur(float n) { nur = n; }
float getNur() { return nur; }
void setSum2() { sum2 = eng + math + com + nur; }
float getSum2() { return sum2; }
};
二、男學生成績輸入並用函數排序輸出
int main()
{
int i, n;
boy *b;
string id, name;
float eng, math, com, mil;
cout<<"有多少男生?";
cin>>n;
b = new boy[n];
for(i = 0; i < n; i++)
{
cout<<"請輸入第"<<i+1<<"個學生的 學號 姓名 英文 數學 程式 軍訓成績:\n";
cin>>id>>name>>eng>>math>>com>>mil;
b[i].setId(id);
b[i].setName(name);
b[i].setEng(eng);
b[i].setMath(math);
b[i].setCom(com);
b[i].setMil(mil);
b[i].setSum2();
}
cout<<"排序中..\n";
rank(b, n);
delete [] b;
system("pause");
}
void rank(boy *b, int n)
{
int i, j;
boy t;
for(i = 0; i < n - 1; i++)
{
for(j = i + 1; j < n; j++)
{
if(b[i].getSum2() < b[j].getSum2())
{
t = b[i];
b[i] = b[j];
b[j] = t;
}
}
}
cout<<"名次\t學號\t姓名\t英文\t數學\t程式\t軍訓\t總分\n\n";
for(i = 0; i < n; i++)
{
cout << i+1 << '\t'
<< b[i].getId() << '\t'
<< b[i].getName() << '\t'
<< b[i].getEng() << '\t'
<< b[i].getMath() << '\t'
<< b[i].getCom() << '\t'
<< b[i].getMil() << '\t'
<< b[i].getSum2() << '\n';
}
}
三、承上,改女學生
只要把Mil改成Nur、boy改girl就可以
int main()
{
int i, n;
girl *g;
string id, name;
float eng, math, com, nur;
cout<<"有多少女生?";
cin>>n;
g = new girl[n];
for(i = 0; i < n; i++)
{
cout<<"請輸入第"<<i+1<<"個學生的 學號 姓名 英文 數學 程式 護理成績:\n";
cin>>id>>name>>eng>>math>>com>>nur;
g[i].setId(id);
g[i].setName(name);
g[i].setEng(eng);
g[i].setMath(math);
g[i].setCom(com);
g[i].setNur(nur);
g[i].setSum2();
}
cout<<"排序中..\n";
rank(g, n);
delete [] g;
system("pause");
}
void rank(girl *g, int n)
{
int i, j;
girl t;
for(i = 0; i < n - 1; i++)
{
for(j = i + 1; j < n; j++)
{
if(g[i].getSum2() < g[j].getSum2())
{
t = g[i];
g[i] = g[j];
g[j] = t;
}
}
}
cout<<"名次\t學號\t姓名\t英文\t數學\t程式\t護理\t總分\n\n";
for(i = 0; i < n; i++)
{
cout << i+1 << '\t'
<< g[i].getId() << '\t'
<< g[i].getName() << '\t'
<< g[i].getEng() << '\t'
<< g[i].getMath() << '\t'
<< g[i].getCom() << '\t'
<< g[i].getNur() << '\t'
<< g[i].getSum2() << '\n';
}
}
四、承上 改存學生
這題更簡單 其實是個幌子 直接用stu類別就好
int main()
{
int i, n;
stu *s;
string id, name;
float eng, math, com;
cout<<"有多少學生?";
cin>>n;
s = new stu[n];
for(i = 0; i < n; i++)
{
cout<<"請輸入第"<<i+1<<"個學生的 學號 姓名 英文 數學 程式 成績:\n";
cin>>id>>name>>eng>>math>>com;
s[i].setId(id);
s[i].setName(name);
s[i].setEng(eng);
s[i].setMath(math);
s[i].setCom(com);
s[i].setSum();
}
cout<<"排序中..\n";
rank(s, n);
delete [] s;
system("pause");
}
void rank(stu *s, int n)
{
int i, j;
stu t;
for(i = 0; i < n - 1; i++)
{
for(j = i + 1; j < n; j++)
{
if(s[i].getSum() < s[j].getSum())
{
t = s[i];
s[i] = s[j];
s[j] = t;
}
}
}
cout<<"名次\t學號\t姓名\t英文\t數學\t程式\t總分\n\n";
for(i = 0; i < n; i++)
{
cout << i+1 << '\t'
<< s[i].getId() << '\t'
<< s[i].getName() << '\t'
<< s[i].getEng() << '\t'
<< s[i].getMath() << '\t'
<< s[i].getCom() << '\t'
<< s[i].getSum() << '\n';
}
}
--
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