[討論] 普物 Set 13 簡答
這次是英文閱讀測驗嗎...
感覺像高三在寫Six-Way Paragraph...
題目都超長的............
看了就不大想寫的說OTZ
感覺要看懂題目比要算出答案還難啊!!!!!!
==========================================================
答案和解答對過~基本上正確...
另外~第三題(b)好奇怪...
希望大家可以說說看自己從題目裡面看到了啥資訊...
我看不懂啊OTZ
ε0 = 8.85 * 10^-12 coul^2 / N * m^2
ε0在下面直接用ε表示
1. 3.61 * 10^-9 coul
2. (a) ρr/2ε
(b) ρ(R^2) / 2εr
3. (a) ρr / 3ε (r is a vector)
(b) ρa / 3ε (a is a vector)
※ 20081229補充→今天TA課問助教~助教說這題的意思是把大球裏面挖空一個圓球
※ 出來~然後計算這個挖空的圓球型空洞內的電場~(應該是這樣...)
※ 請大家多多推文討論一下吧~XD
4-1. (a) │ρ│r / 2ε (the magnitude of electric field must be >0, but in
this problem ρ<0 (negative charge))
(b) pipe內電場強度和r呈正比。
(c) Inward.
(d) While r = R = 0.05m,
Emax = 3.11 * 10^6 N/coul
(e) According to condition 1 mentioned in the problem, the field is high
enough to produce an electrical discharge (at r = R).(←懶得打~直接
Copy解答~請自行修改OTZ) (解答這邊說 r = R 是取進似吧~)
4-2. (a) V = │ρ│(R^2 - r^2) / 4ε
(b) 7.77 * 10^4 Volt
5. (a) 2.72 * 10^-14 J
(b) mass of a electron→ 9.11 * 10^-31 kg
condition given in the question→ 3.02 * 10^-31 kg
有興趣可以寫個誤差分析加以討論XDDD
=======================================================
以上。
先跟大家說個Happy New Year 好了XDD
by Ray 081229
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 59.115.10.162
推
12/29 21:00, , 1F
12/29 21:00, 1F
→
12/29 21:01, , 2F
12/29 21:01, 2F
→
12/29 21:02, , 3F
12/29 21:02, 3F
→
12/29 21:11, , 4F
12/29 21:11, 4F
→
12/29 21:12, , 5F
12/29 21:12, 5F
推
12/29 21:34, , 6F
12/29 21:34, 6F
→
12/29 21:57, , 7F
12/29 21:57, 7F
※ 編輯: cranfis 來自: 59.115.2.157 (12/29 22:00)
推
12/30 01:03, , 8F
12/30 01:03, 8F
→
12/30 01:03, , 9F
12/30 01:03, 9F
推
12/30 20:19, , 10F
12/30 20:19, 10F
推
12/30 23:24, , 11F
12/30 23:24, 11F
推
01/04 20:04, , 12F
01/04 20:04, 12F
→
01/04 20:05, , 13F
01/04 20:05, 13F
推
01/04 20:38, , 14F
01/04 20:38, 14F
推
01/04 20:47, , 15F
01/04 20:47, 15F
推
01/04 23:35, , 16F
01/04 23:35, 16F
→
01/05 00:05, , 17F
01/05 00:05, 17F