[普物] 橫波那題

看板NTUBIME102HW作者chieh0206 (ming chieh)時間16年前 (2010/01/13 01:18)推噓5(5推 0噓 5→)

留言10則, 5人參與討論串1/1

Y1=Asin(kx-wt) Y2=Asin(kx+wt+Q) Y1+Y2=2Asin(kx+Q/2)cos(wt+Q/2) 帶入 X=d => kd+Q/2=0 or pi or 2pi ...... => Q=-2kd 所以 Y2=Asin(kx+wt-2kd) ...# -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.242.142

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ansonyu

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※ 編輯: chieh0206 來自: 140.112.242.142 (01/13 01:54) ※ 編輯: chieh0206 來自: 140.112.242.142 (01/13 01:57)

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