[線代] Ax=b 求A矩陣
請問Ax=b
如果知道x跟b,有方法可以求A矩陣嗎
謝謝
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08/20 13:33, , 1F
08/20 13:33, 1F
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08/20 13:34, , 2F
08/20 13:34, 2F
我是在看線性變換時,才思考這個問題
題目是T:微分 4→3
向量空間 V 的一組基 β={1,x,x^2,X^3}
向量空間 W 的一組基 γ= {1,x,x^2}
可以求出線性變換表示矩陣A
那反過來說 A乘上β的線性組合係數 = γ的線性組合係數
[a] [e]
A [b] = [f]
[c] [g]
[d]
例如 X^2微分是2X
[0] [0]
A [0] = [2]
[1] [0]
[0]
這樣x跟b已知,想要反求A矩陣,但不知道要用什麼方法
謝謝
※ 編輯: gamlty99 (1.34.112.229), 08/20/2017 13:51:15
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08/20 13:49, , 3F
08/20 13:49, 3F
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08/20 13:49, 4F
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08/20 14:25, , 5F
08/20 14:25, 5F
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08/20 14:25, 6F
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08/20 14:25, 7F
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08/20 14:26, 8F
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08/20 14:26, 9F
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08/20 14:26, 10F
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08/20 14:26, 11F
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08/20 14:27, 12F
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08/20 14:28, 13F
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08/20 15:08, 14F
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08/20 20:51, , 15F
08/20 20:51, 15F
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08/20 20:51, 16F
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08/20 22:35, , 17F
08/20 22:35, 17F
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08/20 22:37, 18F
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08/21 01:01, , 20F
08/21 01:01, 20F
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08/21 01:02, 21F
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08/21 01:03, 22F
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08/21 01:05, 23F
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08/21 01:05, 24F
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08/21 01:07, 25F
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08/21 01:08, 26F
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08/21 01:09, 27F
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08/21 14:54, , 28F
08/21 14:54, 28F
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08/21 14:54, 29F
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08/21 14:59, , 30F
08/21 14:59, 30F
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08/22 01:20, , 31F
08/22 01:20, 31F
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08/22 17:08, , 32F
08/22 17:08, 32F
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08/22 17:19, , 33F
08/22 17:19, 33F
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08/22 17:20, , 34F
08/22 17:20, 34F