Re: [中學] 高一數學銜接課程的問題
※ 引述《wjx0305 (胖包子~)》之銘言:
: 若不等式|ax+2|≦b,其中b≧0之解為3≦x≦21,則(a,b)=
(21+3)/2 = 12
3-12 <= x-12 <= 21-12
-9 <= x-12 <= 9
|x-12| <= 9
|x/6 - 2| <= 9/6
|-x/6 + 2| <= 3/2
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※ 編輯: JohnMash 來自: 123.194.224.241 (08/13 22:44)
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