一函數在區間I連續、在I/x0可微(x0 in I)
且在x0有極限值a
證明：此函數在I上皆可微且在x0的微分為a
我覺得很直觀，所以不知道該怎麼入手
f在x0上可微<=>極限值in x0存在<=>左極限=右極限
所以前提不就直接證明了嗎？
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 149.172.237.180
→
05/01 07:43, , 1F
05/01 07:43, 1F
推
05/01 11:45, , 2F
05/01 11:45, 2F
→
05/01 15:07, , 3F
05/01 15:07, 3F
→
05/01 15:07, , 4F
05/01 15:07, 4F
→
05/01 22:15, , 5F
05/01 22:15, 5F
→
05/01 22:16, , 6F
05/01 22:16, 6F
→
05/01 22:16, , 7F
05/01 22:16, 7F
推
05/01 22:32, , 8F
05/01 22:32, 8F
推
05/02 00:09, , 9F
05/02 00:09, 9F