[微積] 有點小難的

看板Math作者 (sheila)時間13年前 (2013/02/05 15:41), 編輯推噓0(0推 0噓 9→)
留言9則, 5人參與, 最新討論串1/1
work through the following sequences of substitutions for ∫√〔1+sin^2(x-1)〕 sin(x-1) cos(x-1) dx Q1. u=x-1, following by v=sin(u), then by w=1+v^2 Q2. u=sin(x-1), following by v=sin(u), then by v=1+u^2 Q3. u=1+〔sin^2 (x-1)〕 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.26.28.220
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02/05 16:00, , 1F
步驟不是都給了@@
02/05 16:00, 1F
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02/05 16:03, , 2F
>"<因為不知道該怎麼做
02/05 16:03, 2F
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02/05 16:43, , 3F
Q2抄錯了吧??另外，大推一樓，明明都給好步驟啦
02/05 16:43, 3F
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02/05 16:44, , 4F
看看課本範例，照樣變數變換，注意du跟dx怎麼換就好
02/05 16:44, 4F
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02/05 19:22, , 5F
看就知道平時不燒香..
02/05 19:22, 5F
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02/05 21:03, , 6F
不是平時不燒香...而是我已經畢業很久了!
02/05 21:03, 6F
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02/05 21:03, , 7F
現在突然被問!!線在哪位善心人士幫我一下>"<
02/05 21:03, 7F
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02/05 21:16, , 8F
cos(x-1)dx=dsin(x-1),sin(x-1)dsin(x-1)=(1/2)dsin^
02/05 21:16, 8F
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02/05 21:17, , 9F
2(x-1)=(1/2)d(1+sin^2(x-1))，再用變數變換
02/05 21:17, 9F
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