Re: [線代] rank相加
令B為n*n矩陣，
B = {bij | 對於i=j,bij=1or-1 對於i≠j,bij=0 , i,j=1,2,...,n}
則滿足rank(B+I)+rank(B-I)=n
=>B^2=I
以上為個人想法 大家一起討論
有錯的地方幫忙指正,謝謝
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