Let P(x) be a polynomial of odd degree with real coefficient.
Then the equation p(x) = 0 has at least one root.
Prove this.
如果畫圖出來理解的話，
x趨近無限大 ＊ x趨近負無限大 應該會小於零
如果假設p(X) = An X^n + An-1 X^(n-1) + .... + A0 , An為奇數 , 且大於零
算出來趨近無限大和負無限大都是0
然後我就卡關了Orz
希望有人可以點出我的盲點，感激不盡 ~"~
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突然發現我原本的想法很有問題 ~"~
把X^n提出來之後會變成
An-1 A0
X^n (An + ---- + ... ----- )
X X^n
如果這樣再下去做趨近無限大 & 負無限大
好像也不對 Orz
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※ 編輯: azurequfo 來自: 140.121.218.208 (02/10 17:08)