[線代] 希望有人有空能夠幫忙解一下

看板Math作者 (讓愛進行到底)時間14年前 (2012/01/08 06:47), 編輯推噓0(000)
留言0則, 0人參與, 最新討論串1/1
1.suppose that A is p*p and its rank k satisfies k<p. show that A is singular 2.let A be p*q. prove that A^T*A is singular if the rank of A is strictly less than q. 3.suppose that B is p*q and that A is q*q and nonsingular. Prove that the rank of BA equals the rank of B. 4.suppose that B is p*q and that A is p*p and nonsingular. Prove that the rank of AB equals the rank of B. 5.show that the rank of A*A^T is less than or equal to the rank of A. 6.prove that the rank of A equals that of A^T by proving it first for Gauss-reduced A and then, using problems 3&4, for general A. 7.show that, if A is singular, then A(adjA)=0 and (adjA)A=0, and five an example of a singular matrix A with adjA not equals to 0(in order to show that the result of this problem is true for other than trivial reasons). 8.prove that the adjoint of a singular matrix is singular. 有人有空可以幫忙翻譯嗎?? 感激不盡 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.32.189.59 ※ 編輯: j04cj86 來自: 140.115.26.92 (01/09 19:33)
文章代碼(AID): #1F2CjfIz (Math)