[線代] 複數矩陣 determinant問題

看板Math作者 ( )時間12年前 (2011/09/18 02:03), 編輯推噓3(300)
留言3則, 3人參與, 最新討論串1/1
_ _ _____ For M ∈ M_(n*n)(C).let M be the matrix such that (M)_(ij) = M_(ij) ______ for all i,j, where M_(ij) is the conjugate of M_(ij) _ ______ prove that det(M) = det(M) _ 目前想到,令 M = A + iB ==> M = A - iB ( A,B ∈ M_(n*n)(F) ) _ det(M) = det(A - iB) = ....... 後面部分就卡住了 T T 還是我這樣想法是不好做的 感謝各位解答!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.117.178.152

09/18 03:46, , 1F
把det用Levi-Civita符號展開,qed
09/18 03:46, 1F

09/18 08:23, , 2F
induction 逐列展開
09/18 08:23, 2F

09/18 14:06, , 3F
取共軛複數是ring homomorphism
09/18 14:06, 3F
文章代碼(AID): #1ETE48nP (Math)