[微積] 一題高微有地方不懂

看板Math作者 (小松鼠)時間13年前 (2011/06/08 15:55), 編輯推噓1(101)
留言2則, 1人參與, 最新討論串1/1
Let f(x)=Σn^(-2)sinnx.Show that f is a continuous function on R (1~無限大) and the ∫f(x)dx=Σn^(-3) + 2Σn^(-3). (0~拍/2) 1.3.5.. n=2.4.6... <sol>: The series defining f converges absolutely and uniformly on R by the M-test with Mn=n^(-2). Hence,f is continuous,and termwise integration is permissible ∫f(x)dx = Σn^(-2)∫sinnx dx = Σ(-n^(-3)cosnx)│0,拍/2 (0~拍/2) (1~無限大) (0~拍/2) (1~無限大) Now,cos1/2n拍 is 0 when n is odd and (-1)^(n/2) when n is even. Hence the nth term of the last series is n^(-3) when n is odd, 2n^(-3) when n=2.6.10...and 0 when n =4.8.12... 我從倒數第三行開始就看不懂了 他跟上面的有什麼關係嗎?! 請問有人能解釋看看嗎? 謝謝>"< -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 163.14.6.23

06/08 17:22, , 1F
倒數第三行是要算出你積出來那個sum中每個term的值啊
06/08 17:22, 1F

06/08 17:22, , 2F
因為每個term會因為n的奇偶性而變化 所以分開討論
06/08 17:22, 2F
文章代碼(AID): #1Dxoi89h (Math)