Re: [其他] 6÷2(1+2)=?
知6÷2÷3=1
=6÷2÷(1+2)
=6÷2×1/(1+2)
若依照答案為1的算法 則
=6÷2/3
=6×3/2=9≠1
原式應為6÷(2÷3)才會為9
是否能用這個方式證明原題目答案為1的是少了一個括號呢
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