Re: [閒聊] 每日leetcode已回收
看板Marginalman作者smart0eddie (smart0eddie)時間1年前 (2024/07/09 11:38)推噓0(0推 0噓 1→)留言1則, 1人參與討論串466/1554 (看更多)
2024-07-09
1701. Average Waiting Time
There is a restaurant with a single chef. You are given an array customers,
where customers[i] = [arrivali, timei]:
arrivali is the arrival time of the ith customer. The arrival times are
sorted in non-decreasing order.
timei is the time needed to prepare the order of the ith customer.
When a customer arrives, he gives the chef his order, and the chef starts
preparing it once he is idle. The customer waits till the chef finishes
preparing his order. The chef does not prepare food for more than one
customer at a time. The chef prepares food for customers in the order they
were given in the input.
Return the average waiting time of all customers. Solutions within 10-5 from
the actual answer are considered accepted.
就照著題目敘述刻一個程式跑模擬
這題為什麼會是med啊
class Solution {
public:
double averageWaitingTime(vector<vector<int>>& customers) {
double waitTime = customers[0][1];
int end = customers[0][0] + customers[0][1];
for (int c = 1; c < customers.size(); c++) {
waitTime += customers[c][1];
if (end > customers[c][0]) {
waitTime += end - customers[c][0];
end = end + customers[c][1];
}
else {
end = customers[c][0] + customers[c][1];
}
}
return waitTime / customers.size();
}
};
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