Re: [閒聊] 每日LeetCode已回收

看板Marginalman作者 (穆)時間2年前 (2023/02/22 08:54), 編輯推噓3(300)
留言3則, 3人參與, 2年前最新討論串246/719 (看更多)
之前都用JPTT發廢文每篇都只值1P,來試試看用電腦發可以賺多少== 1011. Capacity To Ship Packages Within D Days 傳輸帶有n個包裹,每個重量<=500,給你一艘載重x的船, 每天照順序載走一些包裹且其總重<=x,問d天之內載完的最小船載重x多少? 1 <= d <= n <= 50000 然後就想到對答案二分搜了 C++ code: class Solution { public: int shipWithinDays(vector<int>& weights, int days) { int ws = weights.size(); int l = *max_element(weights.begin(), weights.end()), r = 25000000; int d = 0, sum = 0; while(l <= r){ int mid = l + (r - l)/2; d = 0; for(int i=0; i<ws; i++){ sum += weights[i]; if(sum > mid){sum = weights[i]; d++;} else if(sum == mid){sum = 0; d++;} } if(sum){sum = 0; d++;} if(d <= days) r = mid - 1; else if(d > days) l = mid + 1; } return l; } }; -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 101.3.144.80 (臺灣) ※ 文章網址: https://www.ptt.cc/bbs/Marginalman/M.1677027282.A.ED0.html

02/22 09:08, 2年前 , 1F
大師
02/22 09:08, 1F

02/22 10:37, 2年前 , 2F
大師
02/22 10:37, 2F

02/22 13:50, 2年前 , 3F
大師
02/22 13:50, 3F
文章代碼(AID): #1ZzMVIxG (Marginalman)
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文章代碼(AID): #1ZzMVIxG (Marginalman)