Re: [閒聊] 每日LeetCode已回收

看板Marginalman作者 (雨とカプチーノ)時間2年前 (2023/01/01 10:49), 編輯推噓0(000)
留言0則, 0人參與, 最新討論串170/719 (看更多)
Given a pattern and a string s, find if s follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in s. EX: Input: pattern = "abba", s = "dog cat cat dog" Output: true Example 2: Input: pattern = "abba", s = "dog cat cat fish" Output: false Example 3: Input: pattern = "aa", s = "dog" Output: false C# CODE: https://i.imgur.com/8TYOxB5.png
-- (づ′・ω・)づ -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 118.241.148.89 (日本) ※ 文章網址: https://www.ptt.cc/bbs/Marginalman/M.1672541390.A.A31.html
文章代碼(AID): #1ZiFJEen (Marginalman)
討論串 (同標題文章)
文章代碼(AID): #1ZiFJEen (Marginalman)