[討論] 求最小特徵值的程式碼

看板MATLAB作者 (小米酒)時間12年前 (2013/05/15 21:26), 編輯推噓0(000)
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A矩陣是包含變數k的矩陣 想求k=1~10的最小特徵值 然後畫出k與最小特徵值的關係圖 程式碼如下,但是一直無法順利執行 請問是哪個環節出了問題呢?(錯誤訊息在最下方) k=1:10; A=[-2 0 0 1 -(0.5)*k 0 0 0 0; 0 -2 0 (0.5)*k 1 -(0.5)*k 0 0 0; 0 0 -2 0 (0.5)*k 1 0 0 0; 1 (0.5)*k 0 -2 0 0 1 -(0.5)*k 0; -(0.5)*k 1 (0.5)*k 0 -2 0 (0.5)*k 1 -(0.5)*k; 0 -(0.5)*k 1 0 0 -2 0 (0.5)*k 1; 0 0 0 1 (0.5)*k 0 -2 0 0; 0 0 0 -(0.5)*k 1 (0.5)*k 0 -2 0; 0 0 0 0 -(0.5)*k 1 0 0 -2]; B=[22 -8 1 -8 2 0 1 0 0; -8 21 -8 2 -8 2 0 1 0; 1 -8 22 0 2 -8 0 0 1; -8 2 0 21 -8 -1 -8 2 0; 2 -8 2 -8 20 -8 2 -8 2; 0 2 -8 1 -8 21 0 2 -8; 1 0 0 -8 2 0 22 -8 1; 0 1 0 2 -8 2 -8 21 -8; 0 0 1 0 2 -8 1 -8 22]; C=inv(A); D=C*B; y=min(eig(D)); plot(k,y); xlabel('k=1~10'); ylabel('minimum eigenvalue'); 出現以下錯誤訊息 ??? Error using ==> vertcat CAT arguments dimensions are not consistent. Error in ==> aa at 2 A=[-2 0 0 1 -(0.5)*k 0 0 0 0; 0 -2 0 (0.5)*k 1 -(0.5)*k 0 0 0; 0 0 -2 0 (0.5)*k 1 0 0 0; 1 (0.5)*k 0 -2 0 0 1 -(0.5)*k 0; -(0.5)*k 1 (0.5)*k 0 -0 (0.5)*k 1 -(0.5)*k; 0 -(0.5)*k 1 0 0 -2 0 (0.5)*k 1;0 0 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.120.109.14
文章代碼(AID): #1HaupryM (MATLAB)