[問題]非線性方程組
時間 t =0:0.2:10
想求解以下的x
如:
F=[x(1)-0.5.*cos(x(3))
x(2)-0.5.*sin(x(3))
x(4)+0.5.*cos(x(6))-1;
x(5)+0.5.*sin(x(6))-1+0.1*t;
x(1)+0.5*cos(x(3))-1+0.5*cos(x(6));
x(2)+0.5*cos(x(3))-1+0.1*t+0.5*cos(x(6))];
-----------------------------------------------------------------------------------------
原本將funcion打在m-file中
function F = myfunc(x,t)
F=[x(1)-0.5*cos(x(3))
x(2)-0.5*sin(x(3))
x(4)+0.5*cos(x(6))-1;
x(5)+0.5*sin(x(6))-1+0.1*t;
x(1)+0.5*cos(x(3))-1+0.5*cos(x(6));
x(2)+0.5*cos(x(3))-1+0.1*t+0.5*cos(x(6))];
接著在命令視窗中以 for 迴圈寫
for t=0:0.2:10
x0=[0.5;0;0;1;0.5;pi/2];
q1=fsolve(@myfunc,x0);
end
但出現了以下
??? Input argument "t" is undefined.
我該如何去修改並完成?
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.124.33.120
推
11/10 22:36, , 1F
11/10 22:36, 1F
推
11/10 22:40, , 2F
11/10 22:40, 2F