[問題] IF指令已回收
e =
102 1
102 1
102 -1
102 1
103 1
103 -1
103 -1
希望找出102時,1和-1的個數是多少
因此1的個數會有3,而-1的個數會有1
幫我看看哪裡有錯
for i=1:length(e)
if e(i,1)==102
c=sum(e(i,2)==1);
d=sum(e(i,2)==-1);
end
end
謝謝大家!!
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