[理工] 位元運算問題
看板Grad-ProbAsk作者earnestgirl (keep my heart calm)時間11年前 (2013/05/20 19:08)推噓0(0推 0噓 10→)留言10則, 2人參與討論串1/1
main()
{ int a = 0, b = 0x00000003, c = 0;
a = a | (1 << 1); // a | = 1 << 1;
a = a | (1 << 2); // a | = 1 << 2;
printf("a = %d\n" , a);
a = a & ~(1 << 2);
printf("a = %d\n" , a);
c = a ^ b;
printf("c = %d\n" , c);
}
輸出: a = 6
a = 2
c = 1
小妹不懂的是以下兩個主要問題:
1. 程式中整個位元運算的邏輯觀念?
2. 為什麼輸出結果第一個a是6? 下一個a是2? 而c是1呢?
麻煩高手幫忙解答，萬分感謝~
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