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看板Grad-ProbAsk作者dielivenow (死月)時間13年前 (2013/01/02 11:37)推噓2(2推 0噓 2→)

留言4則, 2人參與討論串1/1

第11題的(C)小題 Assume that the access time to this cache is 2ns and the main memory access time is 100ns, including all the miss handling. The miss rate of this cache is 5%. What is the speedup if we add a secondary cache that has a 20ns access time and the miss rate of this secondary cache is 10%? 答案：只有cache：2 ns + 5 % * 100 ns = 7 ns 加上secondary cache： 2 ns + 5 % * 20 ns + 1 % * 100ns= 4 ns speedup： 7/4=1.75 請問加上secondary cache列的式子 1 % * 100 ns裡的 1 %是怎樣來的? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.129.23.123

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ddczx

01/02 12:02, , 1^F

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dielivenow

01/02 13:30, , 2^F

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ddczx

01/02 22:34, , 3^F

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