[理工] [線代] 求kernel 答案寫法
|x1-x2| 3
若 L(X)| | X屬於R Find ker(L)
|x2-x3|
|t|
答案是給 ker(L)=|t| t屬於R
|t|
|1|
假如我寫 ker(L)=|1| 。這樣給不給分。算對還是算錯？
|1|
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◆ From: 111.252.190.144
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09/30 14:26, , 1F
09/30 14:26, 1F
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09/30 14:29, , 2F
09/30 14:29, 2F
依照上面
3
若 let t be a linear transformation from R into it self given by
3
t(x,y,z)=(x+2y+3z)(1,2,3) for any vector(x,y,z) in R
(a) find the kernel of t
答案給…
ker(t)={(-2y-3z,y,z)|y,z屬於R}=span{(-2,1,0),(-3,0,1)}
我寫…
(-2t,t,0) (-3t,0,t) t屬於R 這樣對否？
※ 編輯: VB2005 來自: 111.252.190.144 (09/30 15:02)
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09/30 15:03, , 3F
09/30 15:03, 3F
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09/30 15:04, , 4F
09/30 15:04, 4F
對對對。忘了。 除了這點。這樣寫應該對吧~
※ 編輯: VB2005 來自: 111.252.190.144 (09/30 15:07)
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09/30 23:10, , 9F
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